Appendix Thread. App Index Rws() Clms() Majic code line Codings for other Threads, Tables etc) TEST COPY

[DocAElstein]

Coding for last post

' https://excelfox.com/forum/showthread.php/2837-Appendix-Thread-App-Index-Rws()-Clms()-Majic-code-line-Codings-for-other-Threads-Tables-etc-)?p=19586&viewfull=1#post19586
' http://www.eileenslounge.com/viewtopic.php?f=27&t=38973&p=301714#p301714
Sub TransposeABitDifferent()
' Consider a two column, three row selection
 '  a   b
 '  c   d
 '  e   f
Dim vTemp As Variant ' Use variant, and set a  Shift+F9  watch on it ( To do this: Highlight it anywhere in the coding and use keys  Shift+F9  )
' A single column transpose
 Let vTemp = Application.Transpose(Selection.Columns(1))           '  gives  - {"a", "c", "e"}
' Or   we can  Transpose in a different way, with index, and Stuff
 Let vTemp = Application.Index(Selection, Array(1, 2, 3), Array(1, 1, 1))  ' - {"a", "c", "e"}
' What's going on: Excel / Excel VBA is doing what it often does,  along a row, then down a column, sometimes referred to as array type calculations, in this case the argument arrays are followed leading to an output of a form of the 1 dimensions, ("pseudo horizontal") array , as we want. The index works three times on each pair of co ordinates, each time giving the result in the way Index would in the more conventional way for just 1 pair of row and column co ordinates
' using this way we are not restricted to a single column, we can pick any co ordinates we chose.
' The next co ordinates give us a simple single line of all our cell values
Let vTemp = Application.Index(Selection, Array(1, 1, 2, 2, 3, 3), Array(1, 2, 1, 2, 1, 2)) ' {"a", "b", "c", "d", "e", "f"}
' Or
Dim Rws() As Variant, Clms() As Variant
 Let Rws() = Array(1, 1, 2, 2, 3, 3): Clms() = Array(1, 2, 1, 2, 1, 2)
 Let vTemp = Application.Index(Selection, Rws(), Clms()) '                                ' {"a", "b", "c", "d", "e", "f"}
 
' To make a more useful flexible solution, what we need to do is to get those array arguments dynamically from the  Selection
' For both array aguments we need a 6 element 1 dimensional array
' ( we hit a snag generally in these things in that often Excel has those arrays but won't give us them, - typically it may only give us the first value. Noone is quite sure why. There are various tricks found empirically to make Excel give us the full array of values. Usually it involves putting what we actually want to do inside something that encourages Excel to return us all array values. (There may be some parallel to the so called  C S E  action in a spreadsheet to get full array results, noone is quite sure). Herfe is a trick I found, empirically to often work
'  If({1},   here what you want to do   )      I don't always need to do this. During the development of a solution I monitor ma results in  vTemp  , and if I onbl

' The start point is usually to get an array of the size we want of integers, and then fiddle with some maths to get the actual integer values we want
 Let vTemp = Evaluate("=Column(A:F)") '     {1, 2, 3, 4, 5, 6}
'  For a flexible solution we want the   F  Getting at a column letter is often a bit tricky, strangely Excel never made a function for it, whereas getting the column number is usually easy.
'  In our case the column numnber is given by  Selection.clumns.count
 Let vTemp = Selection.Cells.Count   '   6
' there are a few ways to convert that to the appropriat Letter. An address way is convenient
 Let vTemp = Split(Cells(1, 6).Address, "$")(1) '   -  "F"        This splits any row cell in column 6 address, in this example the cell $F$1, by a  "$"  resulting in an array  {"", "F", "1"), we thne take the second element, which has the indice of  1  , (not  2  ,since  such an array starts at the indicie of  0)
 Let vTemp = Split(Cells(1, Selection.Cells.Count).Address, "$")(1)  '   - "F"
 
 Let vTemp = Evaluate("=Column(A:" & Split(Cells(1, Selection.Cells.Count).Address, "$")(1) & ")") '     {1, 2, 3, 4, 5, 6}
' ( To make the next steps easy to follow, we will stay with the  "F"   hard coded then substitute the bit to get it flexible later
 Let vTemp = Evaluate("=Column(A:F)") '     {1, 2, 3, 4, 5, 6}
' Some maths now. There are probably a few ways. We fiddle around a bit.  We try to get it using some numbers we could get dynamically, things typically of the count nature, such as row and column count, which are  3  and  2  in this example
' Rws()
 Let vTemp = Evaluate("=Column(A:F)/2") ' {.5, 1, 1.5, 2, 2.5, 3}
 Let vTemp = Evaluate("=Int(Column(A:F)/2)") ' 0
 Let vTemp = Evaluate("=If({1},Int(Column(A:F)/2))")  '  {0, 1, 1, 2, 2, 3}
 Let vTemp = Evaluate("=Int((Column(A:F)+2)/2)") ' 1
 Let vTemp = Evaluate("=If({1},Int((Column(A:F)+2)/2))") '
 Let vTemp = Evaluate("=If({1},Int((Column(A:F)+(2-1))/2))")
 Let vTemp = Evaluate("=If({1},Int((Column(A:F)+(" & Selection.Columns.Count & "-1))/" & Selection.Columns.Count & "))")
 
 Let vTemp = Evaluate("=If({1},Int((Column(A:" & Split(Cells(1, Selection.Cells.Count).Address, "$")(1) & ")+(" & Selection.Columns.Count & "-1))/" & Selection.Columns.Count & "))")
 Let Rws() = Evaluate("=If({1},Int((Column(A:" & Split(Cells(1, Selection.Cells.Count).Address, "$")(1) & ")+(" & Selection.Columns.Count & "-1))/" & Selection.Columns.Count & "))")

' Clms()
 Let vTemp = Evaluate("=Mod(Column(A:F),2)") ' 1
 Let vTemp = Evaluate("=If({1},Mod(Column(A:F),2))")       ' {0, 1, 0, 1, 0, 1}
 Let vTemp = Evaluate("=If({1},Mod((Column(A:F)-1),2)+1)") ' {1, 2, 1, 2, 1, 2}
 Let vTemp = Evaluate("=If({1},Mod((Column(A:" & Split(Cells(1, Selection.Cells.Count).Address, "$")(1) & ")-1),2)+1)")
 Let Clms() = Evaluate("=If({1},Mod((Column(A:" & Split(Cells(1, Selection.Cells.Count).Address, "$")(1) & ")-1),2)+1)")


Let vTemp = Application.Index(Selection, Rws(), Clms()) '                                ' {"a", "b", "c", "d", "e", "f"}

' Do the Join
Dim StrOut As String
 Let StrOut = Join(vTemp, ";"): Debug.Print StrOut   '       a;b;c;d;e;f
End Sub
'
'
' Ref
' http://www.excelforum.com/excel-programming-vba-macros/1138428-multidimensional-array-to-single-column-range.html
' http://www.excelforum.com/excel-programming-vba-macros/1138627-dividing-the-items-of-an-array-over-multiple-columns.html

Sub SnberOne()  '   http://www.eileenslounge.com/viewtopic.php?p=301714&sid=4705abb7ec796b7a3426c78642d4f638#p301714
 Let Selection.Resize(1, 1).Offset(0, Selection.Columns.Count).value2 = Join(Application.Index(Selection, Evaluate("=If({1},Int((Column(A:" & Split(Cells(1, Selection.Cells.Count).Address, "$")(1) & ")+(" & Selection.Columns.Count & "-1))/" & Selection.Columns.Count & "))"), Evaluate("=If({1},Mod((Column(A:" & Split(Cells(1, Selection.Cells.Count).Address, "$")(1) & ")-1),2)+1)")), VBA.InputBox("separator", , ";")) '       a;b;c;d;e;f
End Sub

[DocAElstein]

Some notes for this main forum post
https://eileenslounge.com/viewtopic.php?f=27&t=39588


https://postimg.cc/RqMKRrNz

_____ Workbook: report.xls ( Using Excel 2007 32 bit )

Row\Col	A	B	C	D	E	F	I	J	K	L	M
1	DATA						REQUIRE
2	DIVISION	POSITION	POSITION REPORTING	LEVEL_NO	empno	code	DIVISION	LEVEL_NO	POSITION	empno	code
3	XX	OZ00301	INDOL	1	E1	LL81	XX	1	OZ00301	E1	LL81
4	XX	LR0201	OZ00301	2	E2	LL82	XX	2	LR0201	E2	LL82
5	XX	LA0101	LR0201	3	E3	LL83	XX	3	LA0101	E3	LL83
6	XX	LA0201	LR0201	3	E4	LL84	XX	4	XX0101	E11	LL91
7	XX	LA0701	LR0201	3	E5	LL85	XX	4	XX0102	E12	LL92
8	XX	XX0502	LA0201	4	E6	LL86	XX	4	XX0103	E13	LL93
9	XX	XX0601	LA0201	4	E7	LL87	XX	4	XX0104	E14	LL94
10	XX	XX1901	LA0201	4	E8	LL88	XX	3	LA0201	E4	LL84
11	XX	XX2101	LA0201	4	E9	LL89	XX	4	XX0501	E17	LL97
12	XX	XX2201	LA0701	4	E10	LL90	XX	4	XX0502	E6	LL86
13	XX	XX0101	LA0101	4	E11	LL91	XX	4	XX0601	E7	LL87
14	XX	XX0102	LA0101	4	E12	LL92	XX	4	XX1901	E8	LL88
15	XX	XX0103	LA0101	4	E13	LL93	XX	4	XX2101	E9	LL89
16	XX	XX0104	LA0101	4	E14	LL94	XX	3	LA0701	E5	LL85
17	XX	XX0201	LA0701	4	E15	LL95	XX	4	XX0201	E15	LL95
18	XX	XX0301	LA0701	4	E16	LL96	XX	4	XX0301	E16	LL96
19	XX	XX0501	LA0201	4	E17	LL97	XX	4	XX2201	E10	LL90

Worksheet: Sheet1

sachin483 https://eileenslounge.com/viewtopic....306780#p306780
i have postion code and reporting postion and in 2 column but i want the format of reporting one below another ie :- 4 level will report to 3 and 3 level report to 2 and 2 level will report to 1 if any level is not there then create blank level for upper postion example in attached File



snb @ https://eileenslounge.com/viewtopic....306884#p306884
The crux in the question
Change the order of items from 1,2,3,3,3,4,4,4,4,4,4,4,4,4
to inserting the '4' items after the '3' item it belongs to (where cells(n,3) matches cells(y,2))
Resulting order: 1,2,3,4,4,4,3,4,4,4,3,4,4,4

Alan, a few hours later https://excelfox.com/forum/showthrea...ll=1#post19938
Change this
1,2, 3 , 3 , 3 , 4 , 4 , 4 , 4, 4 , 4 , 4 . 4 , 4 , 4 , 4 , 4
To this
1,2, 3 , 4 , 4 . 4 , 4 , 3 , 4 , 4 , 4 , 4 , 4 , 3 , 4 , 4 , 4

' or


Change this
1
2
3
3
3
4
4
4
4
4
4
4
4
4
4
4
4
To this
1
2
3
4
4
4
4
3
4
4
4
4
4
3
4
4
4

[DocAElstein]

_____ Workbook: report.xls ( Using Excel 2007 32 bit )

Row\Col	A	B	C	D	E	F	I	J	K	L	M
1	DATA						REQUIRE
2	DIVISION	POSITION	POSITION REPORTING	LEVEL_NO	empno	code	DIVISION	LEVEL_NO	POSITION	empno	code
3	XX	OZ00301	INDOL	1	E1	LL81	XX	1	OZ00301	E1	LL81
4	XX	LR0201	OZ00301	2	E2	LL82	XX	2	LR0201	E2	LL82
5	XX	LA0101	LR0201	3	E3	LL83	XX	3	LA0101	E3	LL83
6	XX	LA0201	LR0201	3	E4	LL84	XX	4	XX0101	E11	LL91
7	XX	LA0701	LR0201	3	E5	LL85	XX	4	XX0102	E12	LL92
8	XX	XX0502	LA0201	4	E6	LL86	XX	4	XX0103	E13	LL93
9	XX	XX0601	LA0201	4	E7	LL87	XX	4	XX0104	E14	LL94
10	XX	XX1901	LA0201	4	E8	LL88	XX	3	LA0201	E4	LL84
11	XX	XX2101	LA0201	4	E9	LL89	XX	4	XX0501	E17	LL97
12	XX	XX2201	LA0701	4	E10	LL90	XX	4	XX0502	E6	LL86
13	XX	XX0101	LA0101	4	E11	LL91	XX	4	XX0601	E7	LL87
14	XX	XX0102	LA0101	4	E12	LL92	XX	4	XX1901	E8	LL88
15	XX	XX0103	LA0101	4	E13	LL93	XX	4	XX2101	E9	LL89
16	XX	XX0104	LA0101	4	E14	LL94	XX	3	LA0701	E5	LL85
17	XX	XX0201	LA0701	4	E15	LL95	XX	4	XX0201	E15	LL95
18	XX	XX0301	LA0701	4	E16	LL96	XX	4	XX0301	E16	LL96
19	XX	XX0501	LA0201	4	E17	LL97	XX	4	XX2201	E10	LL90

Worksheet: Sheet1





Change this
1,2, 3 , 3 , 3 , 4 , 4 , 4 , 4, 4 , 4 , 4 . 4 , 4 , 4 , 4 , 4
To this
1,2, 3 , 4 , 4 . 4 , 4 , 3 , 4 , 4 , 4 , 4 , 4 , 3 , 4 , 4 , 4

' or


Change this
1
2
3
3
3
4
4
4
4
4
4
4
4
4
4
4
4
To this
1
2
3
4
4
4
4
3
4
4
4
4
4
3
4
4
4

[DocAElstein]

Some notes for this main forum post
https://eileenslounge.com/viewtopic.php?f=27&t=39588
This uses something quite smart stumbled across here
https://eileenslounge.com/viewtopic....266691#p266691

If we have a 1 D array of arrays , like form example { {"a", "b"} , { "c", "d" } } , then strangely it acts in our famous App Index Rws() Clms() Magic code line just as if it was an array like this
{"a", "b"
"c", "d" }

Strange , but true.

So in Hans macro from here,
http://www.eileenslounge.com/viewtop...306785#p306785
, or rather the modified one from here ,
http://www.eileenslounge.com/viewtop...306880#p306880
, instead of pasting a 1 D array out each time, so pasting out a line each time, we add that array to an array of arrays, then finally paste out that final array using the App Index Rws() Clms() Magic code line.

Effectively we are doing like this

Sub WonDeeArrayOfArrays() ' https://eileenslounge.com/viewtopic.php?p=266691#p266691
Dim arr1D(1 To 2) As Variant
 Let arr1D(1) = Array("a", "b")
 Let arr1D(2) = Array("c", "d")
Dim arrOut() As Variant
 Let arrOut() = Application.Index(arr1D(), Evaluate("=ROW(1:2)"), Array(1, 2))
 Let arrOut() = Application.Index(arr1D(), Evaluate("=ROW(1:2)"), Evaluate("=COLUMN(A:B)"))
End Sub

Option Explicit
Const SourceDivCol = 1
Const SourcePosCol = 2
Const SourceRepCol = 3
Const SourceLevCol = 4
Const SourceEmpCol = 5
Const SourceCodCol = 6
Const TargetDivCol = 15
Const TargetLevCol = 16
Const TargetPosCol = 17
Const TargetEmpCol = 18
Const TargetCodCol = 19
Dim SourceRow As Long
Dim TargetRow As Long
Dim Cnt As Long
Dim WunDeeArrayOfArrays() As Variant



Sub CreateReportHansAlan2() '
 ReDim WunDeeArrayOfArrays(1 To Cells(1).CurrentRegion.Rows.Count - 2)
    Dim Boss As Range
    Dim Adr As String
    Dim Pos As String
    Application.ScreenUpdating = False
    TargetRow = 2
    Set Boss = Columns(SourceLevCol).Find(What:=1, LookAt:=xlWhole)
    Adr = Boss.Address
    Do
        SourceRow = Boss.Row
        TargetRow = TargetRow + 1
     Let Cnt = Cnt + 1: Let WunDeeArrayOfArrays(Cnt) = Application.Index(Cells, SourceRow, Array(SourceDivCol, SourceLevCol, SourcePosCol, SourceEmpCol, SourceCodCol))
'     Let Range("O" & TargetRow & ":S" & TargetRow & "").Value2 = Application.Index(Cells, SourceRow, Array(1, 4, 2, 5, 6))
'     Let Range("O" & TargetRow & ":S" & TargetRow & "").Value2 = Application.Index(Cells, SourceRow, Array(SourceDivCol, SourceLevCol, SourcePosCol, SourceEmpCol, SourceCodCol))
'        Cells(TargetRow, TargetDivCol).Value = Cells(SourceRow, SourceDivCol).Value
'        Cells(TargetRow, TargetLevCol).Value = Cells(SourceRow, SourceLevCol).Value
'        Cells(TargetRow, TargetPosCol).Value = Cells(SourceRow, SourcePosCol).Value
'        Cells(TargetRow, TargetEmpCol).Value = Cells(SourceRow, SourceEmpCol).Value
'        Cells(TargetRow, TargetCodCol).Value = Cells(SourceRow, SourceCodCol).Value
        Pos = Cells(SourceRow, SourcePosCol).Value
        Call AddKids(Pos)
        Set Boss = Columns(SourceLevCol).Find(What:=1, After:=Boss, LookAt:=xlWhole)
        If Boss Is Nothing Then Exit Do
    Loop Until Boss.Address = Adr
    Application.ScreenUpdating = True
 
 Let Range("O3").Resize(Cells(1).CurrentRegion.Rows.Count - 2, 5).Value2 = Application.Index(WunDeeArrayOfArrays, Evaluate("=ROW(1:" & Cells(1).CurrentRegion.Rows.Count - 2 & ")"), Evaluate("=COLUMN(A:E)"))
End Sub

Sub AddKids(BossPos As String) '
    Dim Child As Range
    Dim Adr As String
    Dim Pos As String
    Set Child = Columns(SourceRepCol).Find(What:=BossPos, LookAt:=xlWhole)
    If Child Is Nothing Then Exit Sub
    Adr = Child.Address
    Do
        SourceRow = Child.Row
        TargetRow = TargetRow + 1
     Let Cnt = Cnt + 1: Let WunDeeArrayOfArrays(Cnt) = Application.Index(Cells, SourceRow, Array(SourceDivCol, SourceLevCol, SourcePosCol, SourceEmpCol, SourceCodCol))
'     Let Range("O" & TargetRow & ":S" & TargetRow & "").Value2 = Application.Index(Cells, SourceRow, Array(SourceDivCol, SourceLevCol, SourcePosCol, SourceEmpCol, SourceCodCol))
'        Cells(TargetRow, TargetDivCol).Value = Cells(SourceRow, SourceDivCol).Value
'        Cells(TargetRow, TargetLevCol).Value = Cells(SourceRow, SourceLevCol).Value
'        Cells(TargetRow, TargetPosCol).Value = Cells(SourceRow, SourcePosCol).Value
'        Cells(TargetRow, TargetEmpCol).Value = Cells(SourceRow, SourceEmpCol).Value
'        Cells(TargetRow, TargetCodCol).Value = Cells(SourceRow, SourceCodCol).Value
        Pos = Cells(SourceRow, SourcePosCol).Value
        Call AddKids(Pos)
        Set Child = Columns(SourceRepCol).Find(What:=BossPos, After:=Child, LookAt:=xlWhole)
        If Child Is Nothing Then Exit Do
    Loop Until Child.Address = Adr
End Sub

Ref
https://eileenslounge.com/viewtopic....266691#p266691
https://www.excelforum.com/excel-new-users-basics/1099995-application-index-with-look-up-rows-and-columns-arguments-as-vba-arrays.html#post4571172
https://www.excelforum.com/tips-and-tutorials/758402-vba-working-with-areas-within-2d-arrays.html#post5408376
https://www.excelforum.com/excel-programming-vba-macros/1328703-copy-1-dim-array-to-and-2-dim-array.html
http://www.eileenslounge.com/viewtopic.php?p=271035#p271035
https://www.ozgrid.com/forum/index.php?thread/1227920-slicing-a-2d-array/&postID=1239241#post1239241
https://eileenslounge.com/viewtopic.php?p=274367&sid=6b84ff6917c71e849aaeaa281d06fc31#p27436
https://eileenslounge.com/viewtopic.php?f=30&t=34217&p=265384#p265384
Ref
https://www.excelforum.com/excel-new...ml#post4571172
https://www.excelforum.com/tips-and-...ml#post5408376
https://www.excelforum.com/excel-pro...dim-array.html
http://www.eileenslounge.com/viewtop...271035#p271035
https://www.ozgrid.com/forum/index.p...41#post1239241 , https://eileenslounge.com/viewtopic....d06fc31#p27436
https://eileenslounge.com/viewtopic....265384#p265384
https://eileenslounge.com/viewtopic....266691#p266691

[DocAElstein]

I missed the point, ( possibly ), with the OPs original data, saying he had like this
1,2, 3 , 3 , 3 , 4 , 4 , 4 , 4, 4 , 4 , 4 . 4 , 4 , 4 , 4 , 4
, but wanted this:
1,2, 3 , 4 , 4 . 4 , 4 , 3 , 4 , 4 , 4 , 4 , 4 , 3 , 4 , 4 , 4
I missed the point ( possibly ) that there could be more than one level 2 and that maybe the levels could go on a lot further above level 4. Maybe that additional information is obvious to most people? It is not to me. The more flexible open ended requirement would explain all the recursioning, explorer tree view type things discussed.

Never mind.. , a restricted scenario could still be useful to investigate for another solution.
Restricted solution
Restrictions:
One Big Boss , level 1
, a deputy who does all his work, Level 2
, or rather organises the line managers, level 3
, who in turn have all the workers organised beneath them, level 4

Macro Sub AlanAlmostGotThePointAgain()
Rem 0 I bring the data into an array in one go, to do some things a bit more efficiently, but this solution is still not a reduce the interaction with the workbook to 2 instances: reading data, writing the result
Rem 1 Based on the restrictions, this simply adds the first few lines in the final data for output, in the re ordered column order.

Rem 2a
A basic formula is used in an “Evaluate Range” type VBA code line. It’s based on a basic spreadsheet formula of the type
=IF(C5:C19=$B$4;ROW(B5:B19);0)
In words, what this is doing is:
For the level 2, the one position 2, LR0201 , is searched for in the POSITION REPORTING column C. The result is returned in the form of spreadsheet row number, and form the test data will look like this


5
6
7
0
0
0
0
0
0
0
0
0
0
0
0

In Rem 3 , this information gives us the count of level 3s, Lvl3s , and then in the first bit of Rem 4, Rem4a , we use this information to from the input array, the information at the correct position in the final output data array , ( using the running count position variable, Dw to give the required position in the final output data array )

Rem 4
This section is a typical inner loop within an outer loop type situation. Rem 4a in the outer loop section deals with the level 3 positions in the final output array, - at each of ( three in the sample data, ) level 3s we have a similar “Evaluate Range” formula to that used previously, - in this case, the formula in Rem 4b , based on this sort of spreadsheet formula,
=IF(C8:C19=$B$5;ROW(C8:C19);0)
, is used to give us the row within the input data to find each set of level 4s reporting to any particular level 3.
For example, on the case of the first outer loop, ( CntInds3 = 1 ) we look for a POSITION REPORTING of LA0101 , and obtain a spread of results of the following form from that single line evaluate range type formula


0
0
0
0
0
13
14
15
16
0
0
0

The inner loop of section Rem 4c deals with giving us the data in the output data array for those ) in the example data, 4 for the first outer loop, ) found level 4s reporting to the level 3 being considered in the outer loop.


Here is a full coding with some extra 'comment notes

'
Sub AlanAlmostGotThePointAgain() '        https://eileenslounge.com/viewtopic.php?p=306916&sid=baf68db6f023ebc9d65767c7abf9e19d#p306916
Rem 0 worksheets data info
Dim Ws1 As Worksheet: Set Ws1 = ThisWorkbook.Worksheets.Item(1)
Dim arrIn() As Variant: Let arrIn() = Ws1.Range("A1").CurrentRegion.Value2                          '    Ws1.Range("A1").CurrentRegion.Resize(Ws1.Range("A1").CurrentRegion.Rows.Count + 1).Value2
Dim arr1DArrays() As Variant ' https://eileenslounge.com/viewtopic.php?p=306912#p306912   https://excelfox.com/forum/showthread.php/2837-Appendix-Thread-App-Index-Rws()-Clms()-Majic-code-line-Codings-for-other-Threads-Tables-etc-)?p=19940&viewfull=1#post19940    https://excelfox.com/forum/showthread.php/2837-Appendix-Thread-App-Index-Rws()-Clms()-Majic-code-line-Codings-for-other-Threads-Tables-etc-)/page54#post19940
 ReDim arr1DArrays(1 To UBound(arrIn(), 1)) '                                                                         ReDim arr1DArrays(1 To UBound(arrIn(), 1) - 1)                                                    ' Each element will be a row in the final output - see links in last line
Dim Lr As Long: Let Lr = UBound(arrIn(), 1)
Rem 1 some initial lines in the final output, based on the   Restrictions  of  one Boss and 1 deputy, so in other words one level 1 and one level 2
 Let arr1DArrays(1) = Application.Index(Ws1.Cells, 1, Array(1, 4, 2, 5, 6))     '   Ws1.Range("A1:E1").Value2  '
 Let arr1DArrays(2) = Application.Index(Ws1.Cells, 2, Array(1, 4, 2, 5, 6))
 Let arr1DArrays(3) = Application.Index(Ws1.Cells, 3, Array(1, 4, 2, 5, 6))
 Let arr1DArrays(4) = Application.Index(Ws1.Cells, 4, Array(1, 4, 2, 5, 6))
Rem 2a
Dim Dw As Long: Let Dw = 4 ' The main data row for output.  Dw is like a running count keeping note of the next line to add output data to
                                                                                                                     'Dim Lvl As Long: Let Lvl = 2
Dim srchVl As String: Let srchVl = arrIn(Dw, 2)
Dim arrInds3() As Variant: Let arrInds3() = Ws1.Evaluate("=IF(C5:C" & Lr & "=$B$4,ROW(B5:B" & Lr & "),0)")
Rem 3b
Dim Inds3 As Long
    For Inds3 = 1 To UBound(arrInds3(), 1)
     If arrInds3(Inds3, 1) = 0 Then: Dim Lvl3s As Long: Let Lvl3s = Inds3 - 1: Exit For
                                                                                                                                '    If arrInds3(Inds3, 1) = 0 Then Let Dw = Dw + Inds3 + 2: Dim Lvl3s As Long: Let Lvl3s = Inds3 - 1: Exit For
                                                                                                                                ' Let arr1DArrays(arrInds3(Inds3, 1) - 2) = Application.Index(Ws1.Cells, arrInds3(Inds3, 1), Array(1, 4, 2, 5, 6))
    Next Inds3
Rem 4
Rem 4a
'  now we want to investigate all the level 4s reporting to all the level 3s
Dim CntInds3 As Long ' Looping all level 3s
    For CntInds3 = 1 To Lvl3s ' Looping all level 3s
     Let Dw = Dw + 1
     Let arr1DArrays(Dw) = Application.Index(Ws1.Cells, 5 + CntInds3 - 1, Array(1, 4, 2, 5, 6))
    Rem 4b
    Dim arrInds4() As Variant: Let arrInds4() = Ws1.Evaluate("=IF(C" & 5 + Lvl3s & ":C" & Lr & "=$B$" & 5 + CntInds3 - 1 & ",ROW(C" & 5 + Lvl3s & ":C" & Lr & "),0)")
    Rem 4c
    Dim CntInds4s As Long
        For CntInds4s = 1 To UBound(arrInds4(), 1)
            If arrInds4(CntInds4s, 1) = 0 Then
            
            Else
             Let Dw = Dw + 1 '
             Let arr1DArrays(Dw) = Application.Index(Ws1.Cells, arrInds4(CntInds4s, 1), Array(1, 4, 2, 5, 6))
            End If
        Next CntInds4s
    Next CntInds3

Rem 5 Output - convert the 1D array of 1D array output rows to a 2D range form
 Let Range("AE1").Resize(Lr, 5).Value2 = Application.Index(arr1DArrays(), Evaluate("=ROW(1:" & Lr & ")"), Evaluate("=COLUMN(A:E)"))
End Sub

---

Final results and simplified coding in next posts

[DocAElstein]

Sub AlanReporting() '    https://excelfox.com/forum/showthread.php/2837-Appendix-Thread-App-Index-Rws()-Clms()-Majic-code-line-Codings-for-other-Threads-Tables-etc-)?p=19941&viewfull=1#post19941
Dim Ws1 As Worksheet: Set Ws1 = ThisWorkbook.Worksheets.Item(1)
Dim arrIn() As Variant: Let arrIn() = Ws1.Range("A1").CurrentRegion.Value2
Dim arr1DArrays() As Variant: ReDim arr1DArrays(1 To UBound(arrIn(), 1)) '
Dim Lr As Long: Let Lr = UBound(arrIn(), 1)
Rem 1 some initial lines in the final output, based on the   Restrictions  of  one Boss and 1 deputy, so in other words one level 1 and one level 2
 Let arr1DArrays(1) = Application.Index(Ws1.Cells, 1, Array(1, 4, 2, 5, 6)): arr1DArrays(2) = Application.Index(Ws1.Cells, 2, Array(1, 4, 2, 5, 6)): arr1DArrays(3) = Application.Index(Ws1.Cells, 3, Array(1, 4, 2, 5, 6)): arr1DArrays(4) = Application.Index(Ws1.Cells, 4, Array(1, 4, 2, 5, 6))
Rem 2a
Dim Dw As Long: Let Dw = 4
Dim srchVl As String: Let srchVl = arrIn(Dw, 2)
Dim arrInds3() As Variant: Let arrInds3() = Ws1.Evaluate("=IF(C5:C" & Lr & "=$B$4,ROW(B5:B" & Lr & "),0)")
Rem 3b
Dim Inds3 As Long
    For Inds3 = 1 To UBound(arrInds3(), 1)
     If arrInds3(Inds3, 1) = 0 Then: Dim Lvl3s As Long: Let Lvl3s = Inds3 - 1: Exit For
    Next Inds3
Rem 4a
'  now we want to investigate all the level 4s reporting to all the level 3s
Dim CntInds3 As Long ' Outer loop, Looping all level 3s ' ===================================================
    For CntInds3 = 1 To Lvl3s ' Looping all level 3s
     Let Dw = Dw + 1
     Let arr1DArrays(Dw) = Application.Index(Ws1.Cells, 5 + CntInds3 - 1, Array(1, 4, 2, 5, 6))
    Rem 4b
    Dim arrInds4() As Variant: Let arrInds4() = Ws1.Evaluate("=IF(C" & 5 + Lvl3s & ":C" & Lr & "=$B$" & 5 + CntInds3 - 1 & ",ROW(C" & 5 + Lvl3s & ":C" & Lr & "),0)")
    Rem 4c
    Dim CntInds4s As Long ' Inner loop, Looping all level 4s for a level 3 ' --------------------------------
        For CntInds4s = 1 To UBound(arrInds4(), 1)
            If arrInds4(CntInds4s, 1) = 0 Then
            
            Else
             Let Dw = Dw + 1 '
             Let arr1DArrays(Dw) = Application.Index(Ws1.Cells, arrInds4(CntInds4s, 1), Array(1, 4, 2, 5, 6))
            End If
        Next CntInds4s ' ------------------------------------------------------------------------------------
    Next CntInds3 ' =========================================================================================
Rem 5 Output - convert the 1D array of 1D array output rows to a 2D range form
 Let Range("AE1").Resize(Lr, 5).Value2 = Application.Index(arr1DArrays(), Evaluate("=ROW(1:" & Lr & ")"), Evaluate("=COLUMN(A:E)"))
End Sub

_____ Workbook: report.xls ( Using Excel 2007 32 bit )

Row\Col	AE	AF	AG	AH	AI
1	DATA
2	DIVISION	LEVEL_NO	POSITION	empno	code
3	XX	1	OZ00301	E1	LL81
4	XX	2	LR0201	E2	LL82
5	XX	3	LA0101	E3	LL83
6	XX	4	XX0101	E11	LL91
7	XX	4	XX0102	E12	LL92
8	XX	4	XX0103	E13	LL93
9	XX	4	XX0104	E14	LL94
10	XX	3	LA0201	E4	LL84
11	XX	4	XX0502	E6	LL86
12	XX	4	XX0601	E7	LL87
13	XX	4	XX1901	E8	LL88
14	XX	4	XX2101	E9	LL89
15	XX	4	XX0501	E17	LL97
16	XX	3	LA0701	E5	LL85
17	XX	4	XX2201	E10	LL90
18	XX	4	XX0201	E15	LL95
19	XX	4	XX0301	E16	LL96

Worksheet: Sheet1

[DocAElstein]

We note a slight difference in order presented in the final results for the level 4s,
https://excelfox.com/forum/showthrea...ll=1#post19943
https://bit.ly/3LpFarN
, when compared with results from the other solutions so far given
https://excelfox.com/forum/showthrea...ll=1#post19944
https://bit.ly/3L5bLBV

- This sort of difference is commonly seen when comparing explorer / recursioning type solutions with simpler looping ones which build up the results one line after the other - recursioning type solutions go up and down the explorer tree view structure thingy and so often order the final results a bit differently.






_____ Workbook: report.xls ( Using Excel 2007 32 bit )

Row\Col	I	J	K	L	M	AE	AF	AG	AH	AI
1	REQUIRE					DATA
2	DIVISION	LEVEL_NO	POSITION	empno	code	DIVISION	LEVEL_NO	POSITION	empno	code
3	XX	1	OZ00301	E1	LL81	XX	1	OZ00301	E1	LL81
4	XX	2	LR0201	E2	LL82	XX	2	LR0201	E2	LL82
5	XX	3	LA0101	E3	LL83	XX	3	LA0101	E3	LL83
6	XX	4	XX0101	E11	LL91	XX	4	XX0101	E11	LL91
7	XX	4	XX0102	E12	LL92	XX	4	XX0102	E12	LL92
8	XX	4	XX0103	E13	LL93	XX	4	XX0103	E13	LL93
9	XX	4	XX0104	E14	LL94	XX	4	XX0104	E14	LL94
10	XX	3	LA0201	E4	LL84	XX	3	LA0201	E4	LL84
11	XX	4	XX0501	E17	LL97	XX	4	XX0502	E6	LL86
12	XX	4	XX0502	E6	LL86	XX	4	XX0601	E7	LL87
13	XX	4	XX0601	E7	LL87	XX	4	XX1901	E8	LL88
14	XX	4	XX1901	E8	LL88	XX	4	XX2101	E9	LL89
15	XX	4	XX2101	E9	LL89	XX	4	XX0501	E17	LL97
16	XX	3	LA0701	E5	LL85	XX	3	LA0701	E5	LL85
17	XX	4	XX0201	E15	LL95	XX	4	XX2201	E10	LL90
18	XX	4	XX0301	E16	LL96	XX	4	XX0201	E15	LL95
19	XX	4	XX2201	E10	LL90	XX	4	XX0301	E16	LL96

Worksheet: Sheet1

[DocAElstein]

Some extra notes for this Thread:
http://www.eileenslounge.com/viewtopic.php?f=30&t=38460

Hans Solution http://www.eileenslounge.com/viewtop...297266#p297266
This is a nice solution which I totally misread, or rather in my ignorance, I did not understand.

The main point I missed is…
The solution assumes that the final solution actually has a 26 element 1 dimensional array, and the weight numbers in that array are sorted in alphabetical order, so that the first element represents the weight for “A” and the last Element represents the weight for “Z”, etc.
( So the array Letters() is redundant, and only the Weights() array is needed )
Hans has kindly set me straight and explained where I was going wrong. The final working version of his solution is

Sub Testit()
 MsgBox prompt:=Weight("ZAC")
End Sub
' https://eileenslounge.com/viewtopic.php?f=30&t=38460&sid=4295ec4560088f42492ca29590271a87
Public Function Weight(S As String) As Long ' http://www.eileenslounge.com/viewtopic.php?p=297266#p297266
Dim Weights() As Variant  ' Letters() As Variant,
Dim i As Long
'    Letters = Array("A", "B", "C", ..., "Z")
'    Weights = Array(1, 5, 3, ..., 2)
 '                     A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z
 Let Weights() = Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2) ' Watch : - : Weights() :  : Variant/Variant(0 to 25) : Module1.Weight
    For i = 1 To Len(S)
     Let Weight = Weight + Weights(Asc(Mid(S, i, 1)) - 65)
    Next i
End Function

How is that working:
We are looping through each character, then doing something clever to get the running total. The clever bit is getting the array element
To demonstrate that working consider a couple of examples for the case of a word having an A and a Z in it
A has the Ascii Code number of 65. So we end up referring to Weights(65-65) = Weights(0) , which is the first element typically in a 1 dimensional array that starts at indicia 0
Z has the Ascii Code number of 90. So we end up referring to Weights(90-65) = Weights(25) , which is the last element in a 1 dimensional array of 26 elements that starts at indicia 0



In order for the function to get correct results in the case of lower case letters, then one way to do it, ( assuming you have the correct Weights() array you want for lower case letters), you would need to change the 65 to 97

Sub Testit()
Debug.Print Tab(4); "ASCII"; Tab(12); "Weight"
Debug.Print Tab(4); "Code"
 Call Weight("ZAC")
Debug.Print
 Call WeightLowerCase("zac")
End Sub
' https://eileenslounge.com/viewtopic.php?f=30&t=38460&sid=4295ec4560088f42492ca29590271a87
Public Function Weight(S As String) As Long ' http://www.eileenslounge.com/viewtopic.php?p=297266#p297266
Dim Weights() As Variant  ' Letters() As Variant,
Dim i As Long
 '                     A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z
 Let Weights() = Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2) ' Watch : - : Weights() :  : Variant/Variant(0 to 25) : Module1.Weight
    For i = 1 To Len(S)
     Let Weight = Weight + Weights(Asc(Mid(S, i, 1)) - 65)
     Debug.Print Mid(S, i, 1); Tab(4); Asc(Mid(S, i, 1)); Tab(8); Asc(Mid(S, i, 1)) - 65; Tab(12); Weights(Asc(Mid(S, i, 1)) - 65)
    Next i
End Function
Public Function WeightLowerCase(S As String) As Long ' http://www.eileenslounge.com/viewtopic.php?p=297266#p297266
Dim Weights() As Variant  ' Letters() As Variant,
Dim i As Long
 '                     a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z
 Let Weights() = Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2) '
    For i = 1 To Len(S)
     Let WeightLowerCase = WeightLowerCase + Weights(Asc(Mid(S, i, 1)) - 97)
     Debug.Print Mid(S, i, 1) & vbTab & Asc(Mid(S, i, 1)) & vbTab & Asc(Mid(S, i, 1)) - 97 & vbTab & Weights(Asc(Mid(S, i, 1)) - 97)
    Next i
End Function

Here is the Debug.Print output from the last demo coding

   ASCII   Weight
   Code
Z   90  25  2 
A   65  0   1 
C   67  2   3 

z   122 25  2
a   97  0   1
c   99  2   3

[DocAElstein]

Here is an alternative single liner ( almost ## ) type solution to the last post. It was much simpler than I expected, and ends up much shorter than these solutions of mine usually do. (## There was a small snag, not solved yet, which means I have to do it in 2 code lines for now. I may take a look at that later here: https://excelfox.com/forum/showthrea...ll=1#post16655 )

Solution explanation.
Part 1. Background
This is all to do with
_ “my”** ____arrOut()=Index(ArrIn(), Rws(), Clms()) ______ type solutions, ( https://www.excelforum.com/excel-new...ml#post4571172 )
and also
_ using the Match in a similar way – ( some time ago I obsessed with trying out Application.Match where the first argument is an array, in a similar way to those of those array arguments Rws() and Clms() in Index. I got so obsessed I littered a sub forum with over long posts until they deleted them all and limited the post size to stop me doing it again. With hindsight, not a bad thing to do, as I could not see the wood for the trees back then. I can now, and its not at all difficult to understand, so I really don’t need all that crap anymore. Let me call that for now “my” **
________arrOut() = Match(arrArg1(), arrIn() , 0 ) ___ type solution.
( ** I use the word “my” lightly. – I learnt all this stuff from looking at stuff from Rick Rothstein and snb. ( I am not sure if they “invented it” , or got it from other peoples stuff. if I added anything “new” , it might be some of my detailed explanations, which whilst I don’t know if they are correct, they seem to be a valid theory as they go a long way to explain the results ) )


Here is a quick demo of how
_ my ____arrOut()=Match(arrArg1(), arrIn() , 0 ) ____ works
Ordinarily, or most usually the first argument is just one thing that you are looking for. As far as I know all documentation tells you that the way Match in Excel works is, ( simplified ) :
_... you look in the second argument array of things for the thing in the first argument, and , assuming you find it, return the position along where it is, pseudo like
_____ Match( b , { a, b, c } , 0 ) = 2
In the practice we sometimes, ( not always ) , find that things in Excel will work with array arguments and return a corresponding array of outputs. So taking that last example, pseudo like
_____ Match( {b, a} , { a, b, c } , 0 ) = {2, 1}

So that is a bit of theory out of the way. ( I have done a fuller explanation in a few places of how the Application.Index with Look Up Rows and Columns Arguments as VBA Arrays works in a few places
https://excelfox.com/forum/showthrea...ll=1#post16455
https://www.excelforum.com/excel-new...ml#post4571172 )

---

Part 2. Here is my solution examples
Refering to the first long macro below:

Rem1 is just making some stuff I need for the demo. I use the string example of “ZAC” as per the original OP example http://www.eileenslounge.com/viewtopic.php?f=30&t=38460 . For reasons given in the next bit, I make an array of the 26 Ascii Code numbers for the capital alphabet characters, A, B. C ….Z , Asskeys() = { 65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81 ,82,83,84,85,86,87,88,89,90 }
My array of the weights values, Weights(), for the characters will be the same size as Asskeys() and will have the corresponding weight value for each of the 26 characters in the same order.
Once again it will be clear why later. For now, the point is to have arrays of the same size with related things in the same order

 ' '   Ascii Code       65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90
' '                     A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z
' Let Weights() = Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2)  

Rem 2
I found a way on the internet to turn my string example into an array of single characters, which is what I will be feeding into my Match as first argument. ( Unfortunately it does not return in each element the character, but rather its Ascii Code. But for my purposes that’s just as good.

Rem 3 Match
This is the Match bit, and it tells me the position along where I find the three Ascii Code numbers of “ZAC” in the Ascii Code array, Asskeys()
We get from match here, a 3 element array, MtchRes(), of the position along, of the characters in “ZAC” in the array Asskeys(). We have organised that the array of weights is organised in the same order, so this will also be the position along of the corresponding weight number in the array of weights, Weights().
In the example we should have then an array like {26, 1, 3} _ ( if you have followed the logic so far, you can see this is like a pseudo Alphabet position of the characters, Z , A , and C __ (But don’t get confused with Ascii codes, which is pseudo like the official position of characters, and defined by some world standard, that Excel knows about. As example, capital A is listed as Ascii code 65, lowercase a is listed as 97 )

Rem 4 Index
The 3 element array of the position along, of the characters in “ZAC” in the array Asskeys(), is effectively the Clms() array we need for a __arrOut()=Index(ArrIn(), Rws(), Clms())__type solution, where the look up array, arrIn() , will be the weights array, Weights()
The returned array from Index , arrOut(), will be an array, of 3 numbers, which are the weight numbers for the example string “ZAC”.

Rem 5
Finally we simply sum the elements of the found weight values, as per the original OP request.

Sub AssKeys()
Rem 1 Make the arrays and other hard coded things for the demo
Dim AssKeys(1 To 26) As Long
Dim Eye As Long
    For Eye = 65 To 90 Step 1
     Let AssKeys(Eye - 64) = Eye
    Next Eye
' OR
'  Dim AssKeys() As Variant: Let AssKey() = Array(65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90)
Dim Weights() As Variant:
 '   Ascii Code       65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90
 '                     A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z
 Let Weights() = Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2)
Dim ZAC As String
 Let ZAC = "ZAC" ' This is a demo example text string
Rem 2 String to array
Dim arrZAC() As Byte: Let arrZAC() = StrConv(ZAC, vbFromUnicode) ' https://stackoverflow.com/questions/13195583/split-string-into-array-of-characters
Rem 3 Match
Dim MtchRes() As Variant
 Let MtchRes() = Application.Match(arrZAC(), AssKeys(), 0)
Rem 4 Index
Dim arrOut() As Variant
 Let arrOut() = Application.Index(Weights(), 1, MtchRes())
Rem 5
Dim Some As Long: Let Some = Application.Sum(arrOut())
End Sub

Here the shortening possibilities

Sub BeautifulAsskeys()
Rem 1 Make the arrays and other hard coded things for the demo
'Dim Asskeys(1 To 26) As Long
'Dim Eye As Long
'    For Eye = 65 To 90 Step 1
'     Let Asskeys(Eye - 64) = Eye
'    Next Eye
' OR
'  Dim AssKeys() As Variant: Let AssKey() = Array(65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90)
'Dim Weights() As Variant:
' '   Ascii Code       65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90
' '                     A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z
' Let Weights() = Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2)
'Dim ZAC As String
' Let ZAC = "ZAC" ' This is a demo example text string
Rem 2 String to array
Dim arrZAC() As Byte: Let arrZAC() = StrConv("ZAC", vbFromUnicode) ' https://stackoverflow.com/questions/13195583/split-string-into-array-of-characters
Rem 3 Match
'Dim MtchRes() As Variant
' Let MtchRes() = Application.Match(arrZAC(), Asskeys(), 0)
' Let MtchRes() = Application.Match(StrConv(ZAC, vbFromUnicode), Asskeys(), 0)' this does not work
Rem 4 Index
'Dim arrOut() As Variant
' Let arrOut() = Application.Index(Weights(), 1, MtchRes())
Rem 5
Dim Some As Long: Let Some = Application.Sum(Application.Index(Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2), 1, Application.Match(arrZAC(), Array(65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90), 0)))
End Sub
'
Sub AsKeys()                                                       '  http://www.eileenslounge.com/viewtopic.php?p=297288#p297288
Dim arrZAC() As Byte: Let arrZAC() = StrConv("ZAC", vbFromUnicode) ' https://stackoverflow.com/questions/13195583/split-string-into-array-of-characters
Dim Some As Long: Let Some = Application.Sum(Application.Index(Array(1, 5, 3, 1, 4, 3, 2, 1, 6, 4, 5, 3, 2, 1, 2, 3, 4, 5, 6, 7, 6, 5, 4, 3, 2, 2), 1, Application.Match(arrZAC(), Array(65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90), 0)))
End Sub

---

** I use the word “my” lightly. – I learnt all this stuff from looking at stuff from Rick Rothstein and snb. ( I am not sure if they “invented it” , or got it from other peoples stuff. if I added anything “new” , it might be some of my detailed explanations, which whilst I don’t know if they are correct, they seem to be a valid theory as they go a long way to explain the results