VBA Filter for Columns instead of Rows. Phillip Filters
Coding for answer to this Thread
https://www.eileenslounge.com/viewto...p?f=30&t=31740
There are two main routines. They both are event routines reacting when the range A2 : A_ last data row is used.
A selection change routine will make the drop down list the first time that a cell is selected.
A value change routine, ( in the next post ) , makes a filtered range containing just columns having the selected value in that selected row
Private Sub Worksheet_SelectionChange(ByVal Target As Range)
This makes a drop down list in column A when a cell is selected ( The range of ordered values needed to fill the drop down lists is made by this routine and it is placed in a worksheet with Name "DataSaladinValagationLists" )
This is briefly how this routine works:
It only does anything for a selection in the A column range.
It only does anything if there is not already a range of ordered values needed to fill the drop down list for the selected row
The range of data for that row is copied to the clipboard, excluding empty cells . The text held in the clipboard is retrieved.
A row in Excel is held in the clipboard as a string with a vbTab as separator, and this string also has a trailing vbCr & vbLf which we remove. http://www.eileenslounge.com/viewtop...=31395#p242941
A 1 Dimensional array is made from the retrieved string, strSptInDrpPlop() , and this is used to produce a simple string which only has unique cell values in it. This string is then used to replace the strSptInDrpPlop() contents with unique values
The unique values as well as a leading “-“ and trailing “Blank” are pasted out to the worksheet "DataSaladinValagationLists"
Code:
Sub test()
Let Application.EnableEvents = True
Call Worksheet_SelectionChange(Me.Range("A3"))
Let Application.EnableEvents = True
End Sub
' =DataSaladinValagationLists!A2:A3
Private Sub Worksheet_SelectionChange(ByVal Target As Range) ' for initial making of list for drop down
If IsArray(Target.Value) Then Exit Sub
Rem 1 main worksheet data range info
Dim CntItms As Long: Let CntItms = Me.Range("B" & Rows.Count & "").End(xlUp).Row
If Application.Intersect(Target, Me.Range("A2:A" & CntItms & "")) Is Nothing Then Exit Sub ' only do anything for a selection in the A column range.
If Worksheets("DataSaladinValagationLists").Range("A" & Target.Row & "").Value <> "" Then Exit Sub ' We already have made a drop down list - only does anything if there is not already a range of ordered values needed to fill the drop down list for the selected row
Dim CntClms As Long: Let CntClms = Me.Cells.Item(1, Columns.Count).End(xlToLeft).Column
Rem 2 make drop down list for this row
' 2a) get unique list of all values in row
Let Application.EnableEvents = False
Me.Range("C" & Target.Row & "", Me.Cells.Item(Target.Row, CntClms)).SpecialCells(xlCellTypeConstants).Copy ' The range of data for that row is copied to the clipboard, excluding empty cells
Let Application.EnableEvents = True
Dim Dtaobj As Object ' Late Binding equivalent' If you declare a variable as Object, you are late binding it. http://excelmatters.com/2013/09/23/vba-references-and-early-binding-vs-late-binding/
Set Dtaobj = GetObject("New:{1C3B4210-F441-11CE-B9EA-00AA006B1A69}") ' http://excelmatters.com/2013/10/04/late-bound-msforms-dataobject/ http://www.eileenslounge.com/viewtopic.php?f=30&t=31547#p244124
Dtaobj.GetFromClipboard: Dim strClip As String: Let strClip = Dtaobj.GetText()
Let strClip = Left(strClip, Len(strClip) - 2) ' Take off last vbCr & vbLf
Application.CutCopyMode = False ' Clear clipboard, stop screen flicker
Dim strSptInDrpPlop() As String: Let strSptInDrpPlop() = Split(strClip, vbTab, -1, vbBinaryCompare) ' a row in Excel is held as a string with a vbTab as seperator. The array made here may contain duplicated cell values
Dim UnEeks As String: Let UnEeks = " " ' this string will have unique cell values only. I need an initial " " to make sure i can check for a number like " 7 " not just "7" as that might get confused with "27"
Dim Cnt As Long
For Cnt = 0 To UBound(strSptInDrpPlop())
If InStr(1, UnEeks, " " & Trim(strSptInDrpPlop(Cnt)) & " ", vbBinaryCompare) = 0 And Not Trim(strSptInDrpPlop(Cnt)) = "" And Not strSptInDrpPlop(Cnt) = vbTab Then ' I am not sure yet if the last check is needed.
Let UnEeks = UnEeks & Trim(strSptInDrpPlop(Cnt)) & " " ' A similar string to the original retrieved from the clipboard strClip is made with the difference that the seperator is a space and we have no duplicated cell values
Else
End If
Next Cnt
'Let UnEeks = Replace(UnEeks, vbTab, "", 1, -1, vbBinaryCompare) 'remove rogue vbtabs
Let UnEeks = Mid(UnEeks, 2, Len(UnEeks) - 2) ' take off first and last " " ' Left(UnEeks, Len(UnEeks) - 3) ' take off " " & vbCr & vbLf
'Let UnEeks = "-" & " " & UnEeks & "Blanks"
Let strSptInDrpPlop() = Split(UnEeks, " ", -1, vbBinaryCompare) ' Replace the 1 Dimensional array values with only unique values
' 2b) sort list ( Bubble sort )
Dim Eye As Long, Jay As Long
For Eye = 0 To UBound(strSptInDrpPlop()) - 1 'I want to take the next in the array, starting at the first. The process below should result in the smallest being put at this position, because I go through the rest , the inner Jay loop, and when ever i find something smaller i swap so the smalles comes here
For Jay = Eye + 1 To UBound(strSptInDrpPlop()) ' I now go through comparing with each of the rest, the Jays
If IsNumeric(strSptInDrpPlop(Eye)) And IsNumeric(strSptInDrpPlop(Jay)) Then ' This is to overcome an extra problem that I have: I have strings, and VBA thinks that "6" is bigger than "35" but it thinks 6 is less than 35
If CLng(strSptInDrpPlop(Eye)) > CLng(strSptInDrpPlop(Jay)) Then ' This means that I am bigger than the next. So I will swap . I keep doing this which will have the effect of putting the smallest in the current Eye. By the next Eye, I miss out the last, and any previous, which means I effectively do the same which puts the next smallest in this next Eye
Dim Temp As String: Let Temp = strSptInDrpPlop(Jay): Let strSptInDrpPlop(Jay) = strSptInDrpPlop(Eye): Let strSptInDrpPlop(Eye) = Temp
Else
End If
Else ' if we have text, then VBA still allows a comparison to sort - like B > A returns True
If strSptInDrpPlop(Eye) > strSptInDrpPlop(Jay) Then
Let Temp = strSptInDrpPlop(Jay): Let strSptInDrpPlop(Jay) = strSptInDrpPlop(Eye): Let strSptInDrpPlop(Eye) = Temp ' The element being compared with all the rest is bigger, so we swap it. The effect of this is that the smallest in the rest of the list being looked at, ( The Jay loop ) , will finally end up in the current Eye position.
Else
End If
End If
Next Jay
Next Eye
' 2c) paste in values in DataSaladinValagationLists worksheet
With Worksheets("DataSaladinValagationLists")
Let .Range("A" & Target.Row & "").Value = "-" ' ' a leading "-" ,
Let .Cells.Item(Target.Row, 2).Resize(1, UBound(strSptInDrpPlop()) + 1).Value = strSptInDrpPlop() ' unique values
Let .Cells.Item(Target.Row, UBound(strSptInDrpPlop()) + 3).Value = "Blank" ' ' and trailing "Blank"
End With
' 2d) Make dropdown list
Target.Validation.Delete ' This is only necerssary if a drop down is already there
Target.Validation.Add Type:=xlValidateList, AlertStyle:=xlValidAlertStop, Operator:=xlBetween, Formula1:="=DataSaladinValagationLists!A" & Target.Row & ":" & CLDoWhile(UBound(strSptInDrpPlop()) + 3) & "" & Target.Row & ""
End Sub
Sub testieCLDoWhile()
Dim testieletter As String
Let testieletter = CLDoWhile(3) ' should return "C"
End Sub
' CLDoWhile is a Function to get column letter from column number
Function CLDoWhile(ByVal lclm As Long) As String 'Using chr function and Do while loop For example http://www.excelforum.com/excel-programming-vba-macros/796472-how-to-go-from-column-number-to-column-letter.html
Dim rest As Long 'Variable for what is "left over" after subtracting as many full 26's as possible
Do
' Let rest = ((lclm - 1) Mod 26) 'Gives 0 to 25 for Column Number "Left over" 1 to 26. Better than ( lclm Mod 26 ) which gives 1 to 25 for clm 1 to 25 then 0 for 26
' Let FukOutChrWithDoWhile = Chr(65 + rest) & FukOutChrWithDoWhile 'Convert rest to Chr Number, initially with full number so the "units" (0-25), then number of 26's left over (if the number was so big to give any amount of 26's in it, then number of 26's in the 26's left over (if the number was so big to give any amount of 26 x 26's in it, Enit ?
' 'OR
Let CLDoWhile = Chr(65 + (((lclm - 1) Mod 26))) & CLDoWhile
Let lclm = (lclm - (1)) \ 26 'This gives the number of 26's ( if any ), but just the excact part, in the next number down , - so applying the rest formula to this new number will again leave a difference "left over" rest.
'lclm = (lclm - (rest + 1)) \ 26 ' As the number is effectively truncated here, any number from 1 to (rest +1) will do in the formula
Loop While lclm > 0 'Only loop further if number was big enough to still have 0-25's in it
End Function
'
'
Code:
Sub testsort()
Dim df As String, d As String
df = "df"
Dim var
If IsNumeric(df) Then var = CLng(df)
Dim dg As String
dg = "dg"
MsgBox (dg > df) & " " & (dg > d)
MsgBox "7" < "77"
Dim seven As String, seventyseven As String
Let seven = "7": Let seventyseven = "77"
MsgBox seven < seventyseven
If seven < seventyseven Then MsgBox "True"
Dim arrStr(0 To 1) As String
Let arrStr(0) = "7": Let arrStr(1) = "77"
MsgBox arrStr(0) < arrStr(1)
MsgBox "6" < "34" ' FALSE !!!!!!!!!!******************
End Sub
Filter for columns not for rows. Phill Turd Sorted
continued from last post.......
Private Sub Worksheet_Change(ByVal Target As Range)
This reacts to changes of values in column A, for example when selecting a value from the drop down list
Initially a "Blank" selection is changed to "" , and if a "-" was given then the original range is restored
The rest of this routine is very similar to the routine here https://www.eileenslounge.com/viewto...245286#p245218 The difference is that we need here now to determine one set of column indices to use in a code line like pseudo the following to get the required filtered range
Output() = Index ( Cells , allRowIndicies , someColumnIndicies)
( The previous example at that link required all columns and 2 sets of some rows for two outputs based on a column having a Y or not )
Code:
Sub testieCLDoWhile()
Dim testieletter As String
Let testieletter = CLDoWhile(3) ' should return "C"
End Sub
' CLDoWhile is a Function to get column letter from column number
Function CLDoWhile(ByVal lclm As Long) As String 'Using chr function and Do while loop For example http://www.excelforum.com/excel-programming-vba-macros/796472-how-to-go-from-column-number-to-column-letter.html
Dim rest As Long 'Variable for what is "left over" after subtracting as many full 26's as possible
Do
' Let rest = ((lclm - 1) Mod 26) 'Gives 0 to 25 for Column Number "Left over" 1 to 26. Better than ( lclm Mod 26 ) which gives 1 to 25 for clm 1 to 25 then 0 for 26
' Let FukOutChrWithDoWhile = Chr(65 + rest) & FukOutChrWithDoWhile 'Convert rest to Chr Number, initially with full number so the "units" (0-25), then number of 26's left over (if the number was so big to give any amount of 26's in it, then number of 26's in the 26's left over (if the number was so big to give any amount of 26 x 26's in it, Enit ?
' 'OR
Let CLDoWhile = Chr(65 + (((lclm - 1) Mod 26))) & CLDoWhile
Let lclm = (lclm - (1)) \ 26 'This gives the number of 26's ( if any ), but just the excact part, in the next number down , - so applying the rest formula to this new number will again leave a difference "left over" rest.
'lclm = (lclm - (rest + 1)) \ 26 ' As the number is effectively truncated here, any number from 1 to (rest +1) will do in the formula
Loop While lclm > 0 'Only loop further if number was big enough to still have 0-25's in it
End Function
'
'
Sub testieWksChange()
Call Worksheet_Change(Me.Range("A2"))
Let Application.EnableEvents = True ' Just incase it got turned off
End Sub
Private Sub Worksheet_Change(ByVal Target As Range)
If IsArray(Target.Value) Then Exit Sub
Rem 1 main worksheet data range info
Dim CntItms As Long: Let CntItms = Me.Range("B" & Rows.Count & "").End(xlUp).Row
If Application.Intersect(Target, Me.Range("A2:A" & CntItms & "")) Is Nothing Then Exit Sub ' only do anything for a selection in the A column range.
Dim CntClms As Long: Let CntClms = Me.Cells.Item(1, Columns.Count).End(xlToLeft).Column
If Target.Value = "Blank" Then Let Application.EnableEvents = False: Let Target.Value = "": Let Application.EnableEvents = True
Rem 2 test data range reset
If Target.Value = "-" Then
Let Application.EnableEvents = False
Let Me.Range("C1", Me.Cells.Item(CntItms, Worksheets("Sheet1 (2)").Cells.Item(1, Columns.Count).End(xlToLeft).Column)).Value = Worksheets("Sheet1 (2)").Range("C1", Worksheets("Sheet1 (2)").Cells.Item(CntItms, Worksheets("Sheet1 (2)").Cells.Item(1, Columns.Count).End(xlToLeft).Column)).Value
Let Application.EnableEvents = True
Rem 3 Get indices( column numbers) for required columns, and all row indicies
'3a) indices( column numbers) for required columns
Else ' selected value is a unique value or "" for "Blank"
Dim arrLine() As Variant: Let arrLine() = Me.Range(Me.Cells.Item(Target.Row, 1), Me.Cells.Item(Target.Row, CntClms)).Value ' I dont need the first and third column, but it makes it easier to keep track of the correct columns indicie
Dim Cnt As Long
Dim strClms As String: Let strClms = "1 2 " ' For our required columns containing in this row the target selected value
For Cnt = 3 To CntClms ' check columns from 3 for a match to the value in column 1
If CStr(arrLine(1, Cnt)) = CStr(Target.Value) Then ' This is indication of wanted column as it contains the value
Let strClms = strClms & Cnt & " "
Else
End If
Next Cnt
Let strClms = Left(strClms, Len(strClms) - 1) ' Take off last " "
Dim clmsSpt() As String: Let clmsSpt() = Split(strClms, " ", -1, vbBinaryCompare)
Dim Clms() As String: ReDim Clms(1 To UBound(clmsSpt()) + 1) ' for {1,2,7,9} = required columns
For Cnt = 0 To UBound(clmsSpt())
Let Clms(Cnt + 1) = clmsSpt(Cnt)
Next Cnt
'3b) all data ro indicies
Dim Rws() As Variant: Let Rws() = Evaluate("=Row(1:" & CntItms & ")") ' = {1;2;3;4;5;6;7;8;9;.......... , CntItms} = required rows ( all rows are required )
Rem 4 Output filtered columns
Dim arrOut() As Variant: Let arrOut() = Application.Index(Cells, Rws(), Clms())
Let Application.EnableEvents = False
Me.Cells.ClearContents
Let Range("A1").Resize(UBound(arrOut(), 1), UBound(arrOut(), 2)).Value = arrOut()
Let Application.EnableEvents = True
End If
End Sub
Sub testsort()
Dim df As String, d As String
df = "df"
Dim var
If IsNumeric(df) Then var = CLng(df)
Dim dg As String
dg = "dg"
MsgBox (dg > df) & " " & (dg > d)
End Sub
5 Attachment(s)
Sir Narios ... Positioning of procedure separation in the Visual Basic Development Environment
Positioning of procedure separation Line in the Visual Basic Development Environment
These are some notes based on a discussion here.. http://www.eileenslounge.com/viewtopic.php?f=30&t=31756
Lisa Green had noticed something strange in how VBA divides procedures.....
It appears that in VBA, that is to say in the Visual Basic Development Environment Window , ( that window seen by hitting Alt+F11 from a spreadsheet ) , the convention has been set to separate procedures by a line extending across the code pane Window.
We see these as appearing as a series of underscores, __________________ , extending across the Visual Basic Development Environment Window
Code:
End Sub ' The dividing line appears to us as a line of underscores ____
Usually, if we did write exactly this ' The dividing line appears to us as a line of underscores ____ ' , on that terminating line above , then we would not see those underscores, ____ , as they get hidden in the terminating line:
Hidden_____InDividingLine.JPG : https://imgur.com/7DyP9Om
Attachment 2142
The above screenshot shows the simplest case of routines with no “space” in between. In that simple case, the position of the dividing line is as expected in between the procedures. The situation is a bit more complicated if there is a separation in between procedures….
Effect of blank lines ( or ‘commented lines ) In Between
Between procedures we may add blank lines or ' comment lines. If this is done, it appears that the convention has been set to place the line somewhere between the procedures in this blank/ ‘comment range, and the lines above the line “belong” to the procedure above, that is to say the last or preeceding procedure, and the lines below the line “belong” to the procedure below, that is to say the next procedure, http://www.eileenslounge.com/viewtop...=31756#p245845
The documentation is not 100% clear on how the position of the dividing is determined , that is to say how the row on which it physically appears as a long series of underscores, __________________ is determined
There is no obvious logic to the way in which the dividing line can be positioned, that is to say , how to determine on which the dividing line appears as a long series of underscores, __________________
Some initial experiments suggest that is influenced by positioning of blank lines and any single underscores _
Line continuation / Break points : single underscores _
We note in passing , that single underscores are used in coding generally to allow us to divide a single line of code into several lines for ease of reading. For example:
Code:
' http://www.excelfox.com/forum/showthread.php/2293-Move-values-in-rows-at-the-end-of-the-preceding-row-*SOLVED*?p=10891#post10891
Sub LineContunuationUnderscores() ' https://docs.microsoft.com/en-us/dotnet/visual-basic/programming-guide/program-structure/how-to-break-and-combine-statements-in-code
Dim LastRow As Long
LastRow = Cells(Rows.Count, "A").End(xlUp).Row
' Without line breaks
Range("A1:A" & LastRow) = Evaluate(Replace(Replace("IF(ISNUMBER(0+SUBSTITUTE(SUBSTITUTE(A2:A#,"" "",""""),"","","""")),IF(LEFT(A1:A@,4)=""2018"",TRIM(A1:A@&"" ""&A2:A#),""""),IF(LEFT(A1:A@,4)=""2018"",A1:A@,""""))", "#", LastRow + 1), "@", LastRow))
' With Line breaks
LastRow = _
Cells(Rows.Count, "A").End(xlUp).Row
Range("A1:A" & LastRow) = Evaluate(Replace(Replace( _
"IF(ISNUMBER(0+SUBSTITUTE(SUBSTITUTE(" & _
"A2:A#,"" "",""""),"","","""")),IF(LEFT(A1:A@,4)" & _
"=""2018"",TRIM(A1:A@&"" ""&A2:A#),"""")," & _
"IF(LEFT(A1:A@,4)=""2018"",A1:A@,""""))", "#", _
LastRow + 1), "@", LastRow))
' This is _
acceptable in _
or out of a procedure
End Sub
' This is _
acceptable in _
or out of a procedure__________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
Further, we note that the line continuation , sometimes called a line break, _ , also applies to comments whether in a procedure or between procedures:
' This is _
acceptable in _
or out of a procedure
_._________
Determining position of horizontal line dividing procedures when blank or comment lines are between procedures
Sir Narios .
The documentation is not 100% clear on how the position of the dividing is determined , that is to say how the row on which it physically appears as a long series of underscores, __________________ is determined
There is no obvious logic to the way in which the dividing line can be positioned, that is to say , how to determine on which the dividing line appears as a long series of underscores, __________________
Some initial experiments suggest that is influenced by positioning of blank lines and any single underscores _
There appear to be 3 scenarios to consider in order to place the line somewhere in between, ( 4 if you consider the simple case of all lines containing comments or all lines being blank )
Scenario 0
' _(0)
If all lines are blank, or all lines are full with comments ( which exclude line continuations )
No single underscores in any line
The break is immediately after the Last/ upper procedure. (This is the same as the case for no separation between routines )
Scenario 0 .JPG : https://imgur.com/pA4grFL
Attachment 2143
Code:
Sub Scenario_0()
' _(0)
End Sub___________________________________________________________________________________________________________________________________________________________________________________________________________
Sub senario_0()
' _(0)
End Sub_____________________________________________________________________________________________________________________________________________________________________________________________________________________
'
'
'
Sub surnario_0()
' _(0)
End Sub_____________________________________________________________________________________________________________________________________________________________________________________________________________________________
Scenario 1
' _(i) Attachment 2141 SirNario_1.JPG . https://imgur.com/zmr2up2
If no line continuations are present and there is a one or more blank lines, then the line before the first blank line down from the upper routine is taken as the break point.
No single underscores in any line
Code:
Sub Senario_1()
' _(i)
End Sub
'
'________________________________________________________________________________________________________________________________________________________________________________________________________________________________
Sub surnaria_1()
' _(i)
End Sub
'____________________________________________________________________________________________________________________________________________________________________________________________________________________________________
''
'
Sub Sirnario_1()
' _(i)
End Sub_______________________________________________________________________________________________________________________________________________________________________________________________________________
'
'
Sub snaria_1()
' _(i)
End Sub
Scenario 2
' _(ii) Attachment 2144 SirNario_2.JPG : https://imgur.com/D2LqloV
If there are one or more line continuations present then the break point will be placed at the first blank line down after the last line after the line continuation … unless scenario (iii)
Code:
Sub Scnari_2()
' _(ii)
End Sub
''
'
' _
'____________________________________________________________________________________________________________________________________________________________________________________________________________________________________
'
Sub Sernario_2()
' _(ii)
End Sub
'
'
' _
'
'___________________________________________________________________________________________________________________________________________________________________________________________________________________________________
'
Sub Sirnarnio_2()
' _(ii)
End Sub
Scenario 3
' _ (iii) Attachment 2146 SirNario_3.JPG : https://imgur.com/ho56uBN
There are no blank lines after the first line looking down after the last line continuation looking down, or after the first line looking down after the last line continuation looking down all lines contain comments . In this case, the break is at the line after the line on which the line continuation is on.
Code:
Sub scenario_3()
' _(iii)
End Sub
''
' _
____________________________________________________________________________________________________________________________________________________________________________________________________________________________________
'
'
Sub SirNario_3()
' _(iii)
End Sub
'
' _
'____________________________________________________________________________________________________________________________________________________________________________________________________________________________________
'
'
Sub snuaro_3()
' _(iii)
End Sub
'
'
' _
____________________________________________________________________________________________________________________________________________________________________________________________________________________________________
Sub SirNario_3()
End Sub
'
' _
'____________________________________________________________________________________________________________________________________________________________________________________________________________________________________
Sub SurNario_3()
End Sub
"What’s in a String"- VBA break down Loop through character contents of a string
Rotines for this excelfox Thread
http://www.excelfox.com/forum/showth...0943#post10943
This is part 1 of the coding. The second part is in the next post. The second part must be copied directly under this part in the same code module
Code:
Option Explicit '
Option Compare Binary ' https://docs.microsoft.com/de-de/dotnet/visual-basic/language-reference/statements/option-compare-statement
Sub TestWtchaGot()
' In the practice we would likely have our string obtained from some method and would have it held in some string variable
Dim strTest As String ' "Pointer" to a "Blue Print" (or Form, Questionnaire not yet filled in, a template etc.)"Pigeon Hole" in Memory, sufficient in construction to house a piece of Paper with code text giving the relevant information for the particular Variable Type. VBA is sent to it when it passes it. In a Routine it may be given a particular “Value”, or (“Values” for Objects). There instructions say then how to do that and handle(store) that(those). At Dim the created Paper is like a Blue Print that has some empty spaces not yet filled in. A String is a bit tricky. The Blue Print code line Paper in the Pigeon Hole will allow to note the string Length and an Initial start memory Location. This Location well have to change frequently as strings of different length are assigned. Instructions will tell how to do this. Theoretically a special value vbNullString is set to aid in quick checks.. But..http://www.mrexcel.com/forum/excel-questions/361246-vbnullstring-2.html#post44116
Let strTest = Chr(1) & "Hi" & vbCrLf & vbTab & """u."""
Call WtchaGot(strIn:=strTest)
' Call WtchaGot(Chr(1) & "Hi" & vbCrLf & vbTab & """u.""")
End Sub
Sub WtchaGot(ByVal strIn As String)
Rem 1 ' Output "sheet hardcopies"
'1a) Worksheets 'Make a Temporary Sheet, if not already there, in Current Active Workbook, for a simple list of all characters
If Not Evaluate("=ISREF(" & "'" & "WotchaGotInString" & "'!Z78)") Then ' ( the ' are not important here, but iin general allow for a space in the worksheet name like "Wotcha Got In String"
Dim Wb As Workbook ' ' ' Dim: ' Preparing a "Pointer" to an Initial "Blue Print" in Memory of the Object ( Pigeon Hole with a bit of paper or code lines on that can be filled in to refer to a specific Objec of this type ) . This also us to get easily at the Methods and Properties throught the applying of a period ( .Dot) ( intellisense ) '
Set Wb = ActiveWorkbook ' ' Set now (to Active Workbook - one being "looked at"), so that we carefull allways referrence this so as not to go astray through Excel Guessing inplicitly not the one we want... Set: Values are filled at the memory locations and the directions there are specified in the variable "Blue Print "Pointer". In this case a Filled in Blue Print is passed. http://www.excelforum.com/excel-programming-vba-macros/1138804-help-understanding-class-instancing-cant-set-ws-new-worksheet-intellisense-offers-it-4.html#post4387191 '
Wb.Worksheets.Add After:=Wb.Worksheets.Item(Worksheets.Count) 'A sheeet is added and will be Active
Dim ws As Worksheet '
Set ws = ActiveSheet 'Rather than rely on always going to the active sheet, we referr to it Explicitly so that we carefull allways referrence this so as not to go astray through Excel Guessing implicitly not the one we want... Set: Values are filled at the memory locations and the directions there are specified in the variable "Blue Print "Pointer". In this case a Filled in Blue Print is passed. http://www.excelforum.com/excel-programming-vba-macros/1138804-help-understanding-class-instancing-cant-set-ws-new-worksheet-intellisense-offers-it-4.html#post4387191 ' Values are filled at the memory locations and the directions there are specified in the variable "Blue Print "Pointer". In this case a Filled in Blue Print is passed. http://www.excelforum.com/excel-programming-vba-macros/1138804-help-understanding-class-instancing-cant-set-ws-new-worksheet-intellisense-offers-it-4.html#post4387191
ws.Activate: ws.Cells(1, 1).Activate ' ws.Activate and activating a cell sometimes seemed to overcome a strange error
Let ws.Name = "WotchaGotInString"
Else ' The worksheet is already there , so I just need to set my variable to point to it
Set ws = ThisWorkbook.Worksheets("WotchaGotInString")
End If
'1b) Array
Dim myLenf As Long: Let myLenf = Len(strIn) ' ' Long is very simple to handle, - final memory "size" type is known (123.456 and 000.001 have same "size" computer memory ) , and so a Address suggestion can be given for the next line when the variable is filled in. '( Long is a Big whole Number limit (-2,147,483,648 to 2,147,483,647) If you need some sort of validation the value should only be within the range of a Byte/Integer otherwise there's no point using anything but Long.--upon/after 32-bit, Integers (Short) need converted internally anyways, so a Long is actually faster. ) https://www.mrexcel.com/forum/excel-questions/803662-byte-backward-loop-4.html
Dim arrWotchaGot() As String: ReDim arrWotchaGot(1 To myLenf + 1, 1 To 2) ' +1 for header Array for the output 2 column list. The type is known and the size, but I must use this ReDim method simply because the dim statement Dim( , ) is complie time thing and will only take actual numbers
Let arrWotchaGot(1, 1) = Format(Now, "DD MMM YYYY") & vbLf & "Lenf is " & myLenf: Let arrWotchaGot(1, 2) = Left(strIn, 20)
Rem 2 String anylaysis
'Dim myLenf As Long: Let myLenf = Len(strIn)
Dim Cnt As Long
For Cnt = 1 To myLenf ' ===Main Loop========================================================================
' Character analysis: Get at each character
Dim Caracter As Variant ' String is probably OK.
Let Caracter = Mid(strIn, Cnt, 1) ' ' the character in strIn at position from the left of length 1
'2a) The character added to a single WotchaGot long character string to look at and possibly use in coding
Dim WotchaGot As String ' This will be used to make a string that I can easilly see and also is in a form that I can copy and paste in a code line required to build the full string of the complete character string
'2a)(i) Most common characters and numbers to be displayed as "seen normally" ' -------2a)(i)--
If Caracter Like "[A-Z]" Or Caracter Like "[0-9]" Or Caracter Like "[a-z]" Then ' Check for normal characters
Let WotchaGot = WotchaGot & """" & Caracter & """" & " & " ' This will give the sort of output that I need to write in a code line, so for example if I have a123 , this code line will be used 4 times and give like a final string for me to copy of "a" & "1" & "2" & "3" & I would phsically need to write in code like strVar = "a" & "1" & "2" & "3" - i could of course also write = "a123" but the point of this routine is to help me pick out each individual element
Else ' Some other things that I would like to "see" normally - not "normal simple character" - or by a VBA constant, like vbCr vbLf vbTab
Select Case Caracter ' 2a)(ii)_1
Case " "
Let WotchaGot = WotchaGot & """" & " " & """" & " & "
Case "!"
Let WotchaGot = WotchaGot & """" & "!" & """" & " & "
Case "$"
Let WotchaGot = WotchaGot & """" & "$" & """" & " & "
Case "%"
Let WotchaGot = WotchaGot & """" & "%" & """" & " & "
Case "~"
Let WotchaGot = WotchaGot & """" & "~" & """" & " & "
Case "&"
Let WotchaGot = WotchaGot & """" & "&" & """" & " & "
Case "("
Let WotchaGot = WotchaGot & """" & "(" & """" & " & "
Case ")"
Let WotchaGot = WotchaGot & """" & ")" & """" & " & "
Case "/"
Let WotchaGot = WotchaGot & """" & "/" & """" & " & "
Case "\"
Let WotchaGot = WotchaGot & """" & "\" & """" & " & "
Case "="
Let WotchaGot = WotchaGot & """" & "=" & """" & " & "
Case "?"
Let WotchaGot = WotchaGot & """" & "?" & """" & " & "
Case "'"
Let WotchaGot = WotchaGot & """" & "'" & """" & " & "
Case "+"
Let WotchaGot = WotchaGot & """" & "+" & """" & " & "
Case "-"
Let WotchaGot = WotchaGot & """" & "-" & """" & " & "
Case "_"
Let WotchaGot = WotchaGot & """" & "_" & """" & " & "
Case "."
Let WotchaGot = WotchaGot & """" & "." & """" & " & "
' Case " "
' Let WotchaGot = WotchaGot & """" & " " & """" & " & "
' Case " "
' Let WotchaGot = WotchaGot & """" & " " & """" & " & "
' Case " "
' Let WotchaGot = WotchaGot & """" & " " & """" & " & "
' Case " "
' Let WotchaGot = WotchaGot & """" & " " & """" & " & "
' Case " "
' Let WotchaGot = WotchaGot & """" & " " & """" & " & "
' Case " "
' Let WotchaGot = WotchaGot & """" & " " & """" & " & "
